1#include "vmlinux.h"
2#include <bpf/bpf_helpers.h>
3#include <bpf/bpf_core_read.h>
4
5const char LICENSE[] SEC("license") = "GPL";
6
7struct {
8 __uint(type, BPF_MAP_TYPE_ARRAY);
9 __uint(max_entries, 1);
10 __type(key, __u32);
11 __type(value, __u64);
12} array SEC(".maps");
13
14__noinline int sub1(int x)
15{
16 int key = 0;
17
18 bpf_map_lookup_elem(&array, &key);
19 return x + 1;
20}
21
22static __noinline int sub5(int v);
23
24__noinline int sub2(int y)
25{
26 return sub5(y + 2);
27}
28
29static __noinline int sub3(int z)
30{
31 return z + 3 + sub1(4);
32}
33
34static __noinline int sub4(int w)
35{
36 int key = 0;
37
38 bpf_map_lookup_elem(&array, &key);
39 return w + sub3(5) + sub1(6);
40}
41
42
43
44
45static __noinline int sub5(int v)
46{
47 return sub1(v) - 1;
48}
49
50
51
52
53
54__noinline int get_task_tgid(uintptr_t t)
55{
56
57 return BPF_CORE_READ((struct task_struct *)(void *)t, tgid);
58}
59
60int res1 = 0;
61int res2 = 0;
62int res3 = 0;
63int res4 = 0;
64
65SEC("raw_tp/sys_enter")
66int prog1(void *ctx)
67{
68
69
70
71 struct task_struct *t = (void *)bpf_get_current_task();
72
73 if (!BPF_CORE_READ(t, pid) || !get_task_tgid((uintptr_t)t))
74 return 1;
75
76 res1 = sub1(1) + sub3(2);
77 return 0;
78}
79
80SEC("raw_tp/sys_exit")
81int prog2(void *ctx)
82{
83 struct task_struct *t = (void *)bpf_get_current_task();
84
85 if (!BPF_CORE_READ(t, pid) || !get_task_tgid((uintptr_t)t))
86 return 1;
87
88 res2 = sub2(3) + sub3(4);
89 return 0;
90}
91
92static int empty_callback(__u32 index, void *data)
93{
94 return 0;
95}
96
97
98SEC("raw_tp/sys_enter")
99int prog3(void *ctx)
100{
101 struct task_struct *t = (void *)bpf_get_current_task();
102
103 if (!BPF_CORE_READ(t, pid) || !get_task_tgid((uintptr_t)t))
104 return 1;
105
106
107 bpf_loop(1, empty_callback, NULL, 0);
108
109 res3 = sub3(5) + 6;
110 return 0;
111}
112
113
114SEC("raw_tp/sys_exit")
115int prog4(void *ctx)
116{
117 struct task_struct *t = (void *)bpf_get_current_task();
118
119 if (!BPF_CORE_READ(t, pid) || !get_task_tgid((uintptr_t)t))
120 return 1;
121
122 res4 = sub4(7) + sub1(8);
123 return 0;
124}
125